Two of the Geometry box tools are placed on the table as shown. Determine the angle $\angle ABC$
Problem
Source:
Tags: geometry, angles
09.08.2019 13:46
Is the answer $10$ ?
09.08.2019 13:46
yes i got the same
09.08.2019 14:02
extend line $C$ to meet $AB$ at $D$ making line $C$ as transversal $ \angle ADC = 130^{o}$ USING EXTERIOR ANGLE PROPERTY $\angle DCA + \angle CAD = 130^{o}$ $ \angle DCA = 180^{o} - 60^{o}$ = $120^{o}$ THEREFORE $ \angle ABC = 10^{o}$
14.10.2019 18:18
This was RMO???
14.10.2019 18:19
RishiNandha_M wrote: This was RMO??? Actually its confusing. It is between PRMO and RMO
29.10.2024 11:06
Let the set square vertices be CMN where angle M= 90 extend MC too meet AB at K then angle BKC = 50 degree since the ruler opposite sides are parallel angle KCB = 120 (exterior angle property) so in triange KCB -> angle ABC = angle KBC = 10 by angle sum property
29.10.2024 16:58
pentagon ABC(intersection of line c and the ruler top side) total angle is 540, subtract 180+50+300, and you get 10 as the final answer