MathArt4 08.06.2017 04:52 Solve the following system of equations: $$xy^2 = 108$$$$\frac{x^3}{y}= 10^{10}$$
DaniyalQazi2 08.06.2017 05:36 Solution $xy^2=108$ $\frac{x^3}{y}=10^{10}$ $x^3y^6=108^3$ $\frac{x^3}{y}=10^{10}$ Divide $y^7=10^{10}*108^3$ $y^7=2^{16}*5^{10}*3^9$ $y=2^\frac{16}{7}*5^\frac{10}{7}*3^\frac{9}{7}$
Neymess 08.06.2017 20:33 I think it would be $108^3/10^(10)$ instead of what you did, which was multiplying them.