parmenides51 13.09.2020 23:13 Given $x \ge 0$, prove that $$\frac{(x^2 + 1)^6}{2^7}+\frac12 \ge x^5 - x^3 + x$$
sqing 17.09.2020 04:25 parmenides51 wrote: Given $x \ge 0$, prove that $$\frac{(x^2 + 1)^6}{2^7}+\frac12 \ge x^5 - x^3 + x$$ Attachments:
sqing 05.01.2022 11:22 Let $x \ge 0 .$ Prove that $$\frac{11\sqrt 3+9}{36}\left(x^2 + \frac12\right)^3+\frac18 \ge x^5 - x^3 + x$$Equality holds when $x=\frac{\sqrt 3-1}{2}.$