The aim of this problem is that Adu will have the strategy to win. Let Adu choose banana on his first move +) If Bakar chooses banana on his first move, Adu will choose apple on his second move. Now, since Bakar's second move, if he chooses orange, Adu will choose orange; if Bakar choose apple/banana, Adu will choose banana/apple. This will lead to the fact Adu always take the last fruit because the number of fruit after Adu move is always even. +) If Bakar chooses apple/orange, Adu will choose the same as Bakar's $k^{th}$ move. The reason is the same as the first case.